6[x-3]+10=2[3x-4]

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Solution for 6[x-3]+10=2[3x-4] equation:


Simplifying
6[x + -3] + 10 = 2[3x + -4]

Reorder the terms:
6[-3 + x] + 10 = 2[3x + -4]
[-3 * 6 + x * 6] + 10 = 2[3x + -4]
[-18 + 6x] + 10 = 2[3x + -4]

Reorder the terms:
-18 + 10 + 6x = 2[3x + -4]

Combine like terms: -18 + 10 = -8
-8 + 6x = 2[3x + -4]

Reorder the terms:
-8 + 6x = 2[-4 + 3x]
-8 + 6x = [-4 * 2 + 3x * 2]
-8 + 6x = [-8 + 6x]

Add '8' to each side of the equation.
-8 + 8 + 6x = -8 + 8 + 6x

Combine like terms: -8 + 8 = 0
0 + 6x = -8 + 8 + 6x
6x = -8 + 8 + 6x

Combine like terms: -8 + 8 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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